How to Solve Linear and Quadratic Equations — Step-by-Step Methods
Introduction
Solving equations is a foundational skill in mathematics, essential for everything from academic success to real-world problem-solving in engineering, finance, and data analysis. Whether you’re balancing a chemical equation, calculating break-even points in business, or modelling physical phenomena, the ability to isolate variables and find unknown values is indispensable. Learning how to solve linear and quadratic equations—using methods like substitution, factoring, completing the square, and the quadratic formula—builds logical thinking and prepares you for more advanced algebra and calculus. This guide provides a comprehensive, step-by-step walkthrough of each method, explains when to use them, and offers practical examples to help you master equation-solving with confidence and precision.
Understanding Equation Types and Solution Goals
An equation is a mathematical statement that two expressions are equal. The goal of solving an equation is to find the value(s) of the variable(s) that make the equation true—these are called solutions or roots.
1. Linear Equations (First Degree)
A linear equation has the form:
ax + b = 0
where a and b are constants, and a ≠ 0. It has exactly one solution.
Solution Method: Isolate the variable using inverse operations (addition/subtraction, multiplication/division).
Example:
3x – 7 = 8
→ Add 7: 3x = 15
→ Divide by 3: x = 5
2. Quadratic Equations (Second Degree)
A quadratic equation has the form:
ax² + bx + c = 0
where a ≠ 0. It can have 0, 1, or 2 real solutions, depending on the discriminant.
Method 1: Factoring
Best when the quadratic factors neatly into two binomials.
Example:
x² – 5x + 6 = 0
→ Factor: (x – 2)(x – 3) = 0
→ Set each factor to zero: x = 2 or x = 3
Method 2: Quadratic Formula
The universal method that works for all quadratics:
x = [-b ± √(b² – 4ac)] / (2a)
The discriminant D = b² – 4ac determines the nature of the roots:
- D > 0: Two distinct real roots
- D = 0: One real root (repeated)
- D below 0: Two complex conjugate roots
Example:
2x² + 4x – 6 = 0
→ a=2, b=4, c=–6
→ D = 16 + 48 = 64
→ x = [–4 ± 8]/4 → x = 1 or x = –3
Method 3: Completing the Square
Useful for deriving the quadratic formula and solving equations not easily factored.
Steps:
- Move constant to right:
x² + 6x = –5 - Add
(b/2)²to both sides:x² + 6x + 9 = 4 - Write as square:
(x + 3)² = 4 - Take square root:
x + 3 = ±2 - Solve:
x = –1 or x = –5
3. Systems of Linear Equations
A system involves two or more equations with multiple variables. The solution is the point where their graphs intersect.
Substitution Method
- Solve one equation for one variable.
- Substitute into the other equation.
- Solve and back-substitute.
Example:
y = 2x + 1
3x + y = 11
→ Substitute: 3x + (2x + 1) = 11 → 5x = 10 → x = 2
→ y = 5
Elimination Method
- Multiply equations to align coefficients.
- Add/subtract to eliminate one variable.
- Solve and back-substitute.
Example:
2x + 3y = 13
–x + 4y = 5
→ Multiply second by 2: –2x + 8y = 10
→ Add: 11y = 23 → y = 23/11
→ x = 37/11
Pro Tips & Common Mistakes
- Always simplify first: Combine like terms and move all terms to one side before solving.
- Check your solutions: Plug answers back into the original equation to verify.
- Use fractions for precision: Avoid decimals until the final step to prevent rounding errors.
- Watch signs: A common error is mishandling negative signs during distribution or transposition.
- Know when to use each method:
- Factoring: Fast for simple quadratics
- Quadratic formula: Reliable for all cases
- Completing the square: Needed for vertex form or conic sections
- For systems: Use elimination when coefficients are easily aligned; substitution when one equation is already solved for a variable.
Practical Applications
- Finance: Break-even analysis (
Revenue = Cost) - Physics: Kinematic equations (
d = vt + ½at²) - Engineering: Circuit analysis (Ohm’s Law systems)
- Economics: Supply and demand equilibrium
- Computer Science: Algorithm complexity and optimization
- Everyday life: Budgeting, recipe scaling, travel planning
Practice Solving Equations
Linear Equations
- Basic:
5x – 10 = 0→x = 2 - With fractions:
(1/2)x + 4 = 10→x = 12 - Multi-step:
3(x – 4) + 2x = 13→x = 5
Quadratic Equations
- Factoring:
x² + 6x + 8 = 0→(x+2)(x+4)=0→x = –2, –4 - Quadratic formula:
3x² – 10x + 3 = 0→x = 3, 1/3 - Complex roots:
x² + 9 = 0→x = ±3i
Systems of Equations
- Substitution:
y = 2x + 1
3x + y = 11→x=2, y=5 - Elimination:
4x + 2y = 8
–2x + 3y = 11→x=–0.5, y=5 - Word problem:
“A coffee and a muffin cost £4. Two coffees and three muffins cost £10. Find each price.”
→c + m = 4,2c + 3m = 10→c=£2, m=£2
What is the difference between an expression and an equation?
An expression (e.g., 3x + 2) can be simplified but not solved. An equation (e.g., 3x + 2 = 11) contains an equals sign and can be solved for the variable.
Which method is best for solving quadratics?
- Try factoring first—it’s fastest if the equation factors nicely.
- Use the quadratic formula if factoring is difficult or you need a guaranteed method.
- Completing the square is essential for advanced topics like conic sections.
What does a negative discriminant mean?
A negative discriminant (b² – 4ac below 0) means there are no real solutions—only complex ones (e.g., x = –1 ± 2i). This is common in physics when a scenario is physically impossible (e.g., negative time).
How many solutions can a system of two linear equations have?
- One solution: Lines intersect at a point (most common).
- No solution: Lines are parallel (same slope, different intercepts).
- Infinite solutions: Lines are identical (same equation).
Can I solve equations with fractions?
Yes. Multiply both sides by the least common denominator (LCD) to eliminate fractions first.
Example: (x/2) + (x/3) = 5 → Multiply by 6: 3x + 2x = 30 → x = 6
Why do I need to check my solutions?
To catch errors in algebra (e.g., sign mistakes) and to identify extraneous solutions (solutions that don’t satisfy the original equation, common in radical or rational equations).
What if my quadratic won’t factor?
Use the quadratic formula. Every quadratic can be solved this way—even if the roots are irrational or complex.
How do I solve equations with variables on both sides?
Move all variable terms to one side and constants to the other.
Example: 5x – 3 = 2x + 9 → 3x = 12 → x = 4