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Polynomial Division Calculator

Divide polynomials using long division method

📐Long Division Algorithm

Step 1: Divide
Divide the first term of dividend by first term of divisor
Step 2: Multiply
Multiply the entire divisor by the quotient term
Step 3: Subtract
Subtract the product from the dividend
Step 4: Repeat
Continue process with the remainder

💡Example: (x³ + 2x² - 5x + 3) ÷ (x - 1)

Step 1: x³ ÷ x = x²
Step 2: x²(x - 1) = x³ - x²
Step 3: (x³ + 2x²) - (x³ - x²) = 3x²
Step 4: 3x² ÷ x = 3x
Step 5: 3x(x - 1) = 3x² - 3x
Step 6: (3x² - 5x) - (3x² - 3x) = -2x
Step 7: -2x ÷ x = -2
Step 8: -2(x - 1) = -2x + 2
Step 9: (-2x + 3) - (-2x + 2) = 1
Quotient: x² + 3x - 2
Remainder: 1

💼Applications

Algebra
• Simplifying expressions
• Finding factors
• Solving equations
Calculus
• Integration
• Partial fractions
• Limit evaluation
Engineering
• Signal processing
• Control theory
• System analysis

Polynomial Division Calculator: Long Division with Polynomials

Table of Contents - Polynomial Division


How to Use This Calculator - Polynomial Division

Enter the dividend (the polynomial being divided) in the first input field using standard notation like "x³ + 2x² - 5x + 3".

Enter the divisor (what you're dividing by) in the second input field like "x - 2" or "x² + 1".

Click "Calculate" to see the division result. The output shows:

  • The quotient polynomial
  • The remainder (if any)
  • Complete long division work shown step-by-step
  • Verification that divisor times quotient plus remainder equals dividend

Use standard polynomial notation with terms in descending order of degree for clearest results.


What Is Polynomial Division?

Polynomial division works just like long division with numbers, except you're dividing expressions with variables. If you can divide 847 by 7, you can divide polynomials—the process is remarkably similar.

Think about dividing 847 by 7. You ask "how many times does 7 go into 8?" and build the answer digit by digit. With polynomials, you ask "how many times does x go into x³?" and build the answer term by term.

Why this matters: Division reveals factors and simplifies rational expressions. It's essential for partial fraction decomposition, finding zeros of polynomials, and simplifying complex fractions. The remainder theorem connects division to function values.

The key relationship is: Dividend = Divisor times Quotient plus Remainder. For polynomials, if there's no remainder, the divisor is a factor of the dividend.

Understanding polynomial division gives you power to simplify expressions, solve higher-degree equations, and understand the structure of polynomial functions.


How to Divide Polynomials Manually

Basic long division setup:

Divide (x³ + 5x² + 2x - 8) by (x + 2)

Set up like numerical long division:

        x + 2 | x³ + 5x² + 2x - 8

Step 1: Divide leading terms.

x³ divided by x equals x². Write x² above the division line.

              x²
        x + 2 | x³ + 5x² + 2x - 8

Step 2: Multiply divisor by first quotient term.

x²(x + 2) = x³ + 2x²

Write this under the dividend and subtract:

              x²
        x + 2 | x³ + 5x² + 2x - 8
                x³ + 2x²
                ─────────
                     3x² + 2x

Step 3: Bring down next term and repeat.

Divide 3x² by x to get 3x. Add to quotient.

              x² + 3x
        x + 2 | x³ + 5x² + 2x - 8
                x³ + 2x²
                ─────────
                     3x² + 2x
                     3x² + 6x
                     ─────────
                         -4x - 8

Step 4: Continue until degree of remainder is less than divisor.

Divide -4x by x to get -4.

              x² + 3x - 4
        x + 2 | x³ + 5x² + 2x - 8
                x³ + 2x²
                ─────────
                     3x² + 2x
                     3x² + 6x
                     ─────────
                         -4x - 8
                         -4x - 8
                         ───────
                              0

Result: (x³ + 5x² + 2x - 8) / (x + 2) = x² + 3x - 4 with remainder 0.

Example with remainder:

Divide (x³ + 2x + 5) by (x - 1)

Note the missing x² term—treat it as 0x².

              x² + x + 3
        x - 1 | x³ + 0x² + 2x + 5
                x³ - x²
                ───────
                    x² + 2x
                    x² - x
                    ───────
                        3x + 5
                        3x - 3
                        ──────
                            8

Result: (x³ + 2x + 5) / (x - 1) = x² + x + 3 with remainder 8.

Written as: (x³ + 2x + 5) = (x - 1)(x² + x + 3) + 8

Or: (x³ + 2x + 5)/(x - 1) = x² + x + 3 + 8/(x - 1)

Dividing by a quadratic:

Divide (2x⁴ - 3x³ + x² - 5x + 7) by (x² + 1)

              2x² - 3x - 1
    x² + 1 | 2x⁴ - 3x³ + x² - 5x + 7
             2x⁴      + 2x²
             ──────────────
                 -3x³ - x² - 5x
                 -3x³      - 3x
                 ───────────────
                      -x² - 2x + 7
                      -x²      - 1
                      ────────────
                          -2x + 8

Result: Quotient is 2x² - 3x - 1, remainder is -2x + 8.

Checking your work:

Multiply quotient by divisor and add remainder: (x² + 1)(2x² - 3x - 1) + (-2x + 8) should equal original dividend.

Expand: 2x⁴ - 3x³ - x² + 2x² - 3x - 1 - 2x + 8 = 2x⁴ - 3x³ + x² - 5x + 7 ✓

Using placeholder zeros:

Divide (x⁴ - 16) by (x - 2)

Write as x⁴ + 0x³ + 0x² + 0x - 16 to keep terms aligned.

              x³ + 2x² + 4x + 8
        x - 2 | x⁴ + 0x³ + 0x² + 0x - 16
                x⁴ - 2x³
                ────────
                    2x³ + 0x²
                    2x³ - 4x²
                    ─────────
                         4x² + 0x
                         4x² - 8x
                         ────────
                              8x - 16
                              8x - 16
                              ───────
                                   0

Result: (x⁴ - 16)/(x - 2) = x³ + 2x² + 4x + 8


Real-World Applications

Simplifying rational functions. The expression (x³ - 8)/(x - 2) looks complicated, but dividing gives x² + 2x + 4, much simpler (since remainder is 0).

Finding asymptotes in calculus. For y = (2x³ + x² - 1)/(x² + 1), dividing numerator by denominator gives y = 2x + quotient + remainder/(divisor), revealing oblique asymptote y = 2x.

Partial fraction decomposition setup. Before decomposing, improper fractions need division. If numerator degree is greater than or equal to denominator degree, divide first.

Signal processing filter design. Transfer functions are rational expressions. Division helps analyze frequency response and system behavior.

Cryptography and error correction. Polynomial division over finite fields enables Reed-Solomon codes used in QR codes, CDs, and data transmission.

Physics and engineering models. Rational function models often require division to identify dominant terms or asymptotic behavior.


Scenarios People Actually Run Into

Factoring by division. You know x = 3 is a root of x³ - 2x² - 5x + 6, so (x - 3) is a factor. Divide the polynomial by (x - 3) to find the quadratic factor, then solve that.

Simplifying before integrating. Calculus integral of (x³ + 1)/(x + 1) is easier if you divide first: (x³ + 1)/(x + 1) = x² - x + 1, which integrates easily.

Checking if one polynomial divides another. Does (x + 2) divide (x³ + 8)? Divide and check remainder. If it's zero, yes. In this case, x³ + 8 = (x + 2)(x² - 2x + 4).

Finding unknown coefficients. You know (x³ + ax² + bx + 6) divided by (x - 2) gives remainder 0. Use division and the remainder theorem to find a and b.

Analyzing polynomial behavior. For large x, how does (3x⁴ + 2x² - 1)/(x² - 4) behave? Divide to get 3x² + 12 + (51x - 49)/(x² - 4). The quotient 3x² + 12 dominates as x grows.

Verifying factorizations. Someone claims x⁴ - 1 = (x - 1)(x³ + x² + x + 1). Divide x⁴ - 1 by x - 1 to verify the quotient is indeed x³ + x² + x + 1.


Trade-Offs and Decisions People Underestimate

Long division versus synthetic division. For linear divisors (x - a), synthetic division is faster. For quadratic or higher-degree divisors, long division is necessary. Learn both.

When to check for factors first. If you suspect the divisor is a factor, try the remainder theorem first. Plug in the zero and see if you get zero output—faster than full division.

Keeping terms aligned. Missing terms cause errors. Always include placeholder zeros: x⁴ - 1 becomes x⁴ + 0x³ + 0x² + 0x - 1. This alignment prevents mistakes.

Deciding what form to leave the answer. Sometimes quotient plus remainder/divisor is useful: q(x) + r(x)/d(x). Other times, just the quotient matters. Choose based on what you need next.

Dividing before factoring versus factoring before dividing. If the divisor factors easily, factor it first to potentially use simpler divisions. For x² - 1, divide by (x - 1) then (x + 1) instead of by x² - 1 directly.


Common Mistakes and How to Recover

Forgetting placeholder zeros. Dividing x³ - 8 by x - 2 without writing x³ + 0x² + 0x - 8 leads to misalignment and wrong terms. Always write all degrees.

Sign errors during subtraction. Subtracting (x³ + 2x²) means adding -(x³ + 2x²) = -x³ - 2x². Watch signs carefully. Common error: forgetting to distribute the negative.

Not continuing until remainder degree is less than divisor. The remainder must have degree less than the divisor. If dividing by x², remainder should be at most degree 1 (linear).

Dividing terms incorrectly. When dividing 6x² by 2x, the answer is 3x, not 3x². Subtract exponents, don't forget.

Misaligning terms. Writing the subtraction incorrectly or bringing down wrong terms creates cascading errors. Use columnar format with careful alignment.

Forgetting to bring down terms. After each subtraction, bring down the next term from the dividend. Skipping this step breaks the algorithm.


Related Topics

Synthetic division. Faster method for dividing by linear factors (x - a). Same results, less writing.

Remainder theorem. States that dividing f(x) by (x - a) gives remainder f(a). Connects division to function evaluation.

Factor theorem. Says (x - a) is a factor of f(x) if and only if f(a) = 0. Remainder theorem specialized to zero remainder.

Rational root theorem. Identifies potential rational zeros, which lead to linear factors for division.

Partial fraction decomposition. Requires division first when rational expression is improper.

Polynomial factorization. Division helps factor polynomials by removing known factors iteratively.


How This Calculator Works

Input parsing:

Dividend: parse as polynomial with coefficients
Divisor: parse as polynomial with coefficients
Ensure terms in descending order by degree
Add zero coefficients for missing degrees

Long division algorithm:

While degree of current dividend >= degree of divisor:
  Divide leading term of current dividend by leading term of divisor
  Add result to quotient
  Multiply entire divisor by this quotient term
  Subtract from current dividend
  Update current dividend to result
Remainder is final current dividend

Output formatting:

Display quotient polynomial
Display remainder polynomial
Show full long division work step-by-step
Verify: divisor × quotient + remainder = original dividend

Special handling:

Missing terms: insert 0 coefficients
Leading coefficient not 1: factor out if needed
Zero divisor: return error
Constant divisor: divide all coefficients

FAQs

What is polynomial division?

Dividing one polynomial by another using a process similar to long division with numbers. Results in a quotient polynomial and possibly a remainder.

When do I need to use polynomial division?

When simplifying rational expressions, finding factors, performing partial fraction decomposition, or analyzing polynomial functions.

How is it different from synthetic division?

Polynomial long division works for any divisor. Synthetic division only works for linear divisors (x - a) but is faster and more compact.

What is the remainder?

What's left over when division isn't exact. Its degree is always less than the divisor's degree. If remainder is zero, the divisor is a factor.

How do I know if one polynomial divides another?

Perform the division. If the remainder is zero, the divisor divides the dividend evenly—it's a factor.

What's the dividend and what's the divisor?

Dividend is what you're dividing (numerator). Divisor is what you're dividing by (denominator). Quotient is the result.

Why use placeholder zeros?

To keep columns aligned. Missing terms have coefficient zero. Writing them explicitly prevents errors in subtraction and alignment.

Can I divide by any polynomial?

Any non-zero polynomial. Can't divide by zero polynomial. Divisor degree can be anything from 0 (constant) to less than dividend degree for meaningful quotient.

What if the dividend degree is less than divisor degree?

Quotient is 0, remainder is the entire dividend. Like dividing 3 by 5: quotient 0, remainder 3.

How do I check my division?

Multiply quotient by divisor and add remainder. Should equal the original dividend. This verifies correctness.

What is an improper rational expression?

One where numerator degree is greater than or equal to denominator degree. Divide to convert to proper form plus polynomial.

Can the remainder be negative?

Coefficients can be negative, yes. The remainder polynomial can have negative coefficients or even be a negative constant.

How does this relate to the remainder theorem?

Remainder theorem says dividing f(x) by (x - a) gives remainder f(a). Division confirms this—plug in a, get the remainder value.

What if there's a remainder?

Express as: dividend = divisor times quotient plus remainder. Or: dividend/divisor = quotient + remainder/divisor.

Why does descending order matter?

Keeps work organized and terms aligned by degree. Standard convention makes sharing and checking work easier.

Can I divide polynomials with different variables?

Yes, but they act as independent. Dividing (x² + y²) by x gives quotient x plus remainder y². Variables that don't appear in divisor stay in remainder.

What about dividing with fractions?

Coefficients can be fractions. Process is the same. 1/2 x² divided by x gives 1/2 x. Work carefully with fraction arithmetic.

Is there a shortcut for dividing by (x - a)?

Yes—synthetic division. It's specifically designed for linear factors and is much faster than long division.

What happens with complex coefficients?

Same process. Complex numbers follow standard arithmetic. Division works with complex coefficients just like real ones.

How do I find all factors of a polynomial?

Start with one factor (using rational root theorem or graphing). Divide to get quotient. Factor quotient. Repeat until only linear and irreducible quadratic factors remain.

Additional Notes

Polynomial division is fundamental algebra that bridges arithmetic and abstract mathematics. The algorithm mirrors long division you learned with numbers, showing the power of generalization.

Master the technique with practice. Start with simple linear divisors, progress to quadratics, and build confidence with higher degrees. The process is mechanical—follow steps carefully.

Always verify your work by multiplying back. This habit catches errors immediately and reinforces understanding of the division relationship.

Polynomial division appears throughout higher mathematics: calculus, abstract algebra, number theory, and applied fields. Understanding it deeply pays dividends across mathematical disciplines.

The connection to the remainder and factor theorems reveals deep structure in polynomials. Division isn't just computation—it's a tool for understanding polynomial behavior and structure.